# Want Create A New List From Existing List Using If Else Statement

## 15 July 2019 - 1 answer

I want to create a new list using existing list "dta", where i do not want a value for "banana" but a numeric for others. desired list is below:

``````[1,3,4,5,6]
``````

but when i am trying to print of my final list "d" then i get only single value.

``````dta=list(["apple","banana","pine","cucumber","Guava","Coconut"])

d=[]
def cont_list(x):

for i in x:
if i=="banana":
continue
if i=="pine":
d.append(3)

elif i=="apple":
d.append(1)

elif i=="cucumber":
d.append(4)
elif i=="Guava":
d.append(5)
else:
d.append(6)

return d

cont_list(dta)
print(d)
``````

you can do it with list comprehension:

``````dta = ["apple","banana","pine","cucumber","Guava","Coconut"]

d = [idx for idx in range(1,len(dta)+1) if dta[idx-1] != "banana"]
print (d)
``````

in function:

dta=list(["apple","banana","pine","cucumber","Guava","Coconut"])

``````def cont_list(x):
dta = ["apple","banana","pine","cucumber","Guava","Coconut"]
d = [idx for idx in range(1,len(dta)+1) if dta[idx-1] != "banana"]
return d
print (cont_list(dta))
``````

output:

``````[1, 3, 4, 5, 6]
``````

NOTE: your code will be ok if you fix INDENTION:

``````d=[]
def cont_list(x):

for i in x:
if i=="banana":
continue
if i =="pine":
d.append(3)

elif i=="apple":
d.append(1)

elif i=="cucumber":
d.append(4)
elif i=="Guava":
d.append(5)
else:
d.append(6)
return d

cont_list(dta)
print(d)
``````

or you can do it like:

``````d=[]
def cont_list(x):

for i in range(len(x)):
if x[i]=="banana":
continue
else:
d.append(i+1)
return d

cont_list(dta)
print(d)
``````