# Same Code For Python 2 And 3 Gives Different Results

## 20 May 2019 - 1 answer

I have the issue that I run python 3 on my client and the server where I execute the programs run python 2.

So I set up the following script:

``````from math import radians, cos, sin, asin, sqrt, exp
from datetime import datetime
def dateSmoother(a, b):
#Format the date
a = datetime.strptime(a, "%Y-%m-%d")
b = datetime.strptime(b, "%Y-%m-%d")
diff = (a-b).days

return exp(-(diff/h_date)**2)

def timeSmoother(a, b):
# Since we only got readings from two different times
# We first check to see if they are the same
if (a==b):
return exp(-(0/h_time)**2)
else:
return exp(-(12/h_time)**2)

h_date = 30
h_time = 12
a = "2013-11-01"
b = "2013-11-13"
print(dateSmoother(a, b))
print(timeSmoother("06:00:00", "06:00:00"))
print(timeSmoother("06:00:00", "18:00:00"))
``````

When I run it locally with python 3 I get the following output:

``````0.8521437889662113
1.0
0.36787944117144233
``````

However, when I run it on the server I get:

``````0.367879441171
1.0
0.367879441171
``````

The problem lies in the division here `diff/h_date`

From the details mentioned in this answer here or this answer here

• In Python2.7, division of two ints produces an int
``````>>> -12/30
-1
``````
• In Python3, division of two ints produces an float
``````>>> -12/30
-0.4
``````

So depending on what you want

• If you want a float for both cases, import `from __future__ import division` in Python2.7,
``````>>> from __future__ import division
>>> -12/30
-0.4
``````
• If you want a int in both cases, perform integer division `//` in Python3
``````>>> -12//30
-1
``````