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My Discord Bot Gives An Error When I Try Send A Message

- 1 answer

So I was writing a basic Discord bot for fun. And I wanted it to count how many times "lmao was said". So I wrote this in Python:

if 'lmao' in message.content.lower():
    aantlmao=0
    await message.channel.send('aantal keer lmao gezegd:', aantlmao, '(sinds de laatste bot restart)')
    aantlmao=aantlmao+1
    print('counted a LMAO')

The message translates to: amount of times said lmao: [lmaoCounter] (since last bot restart)

But when I type "lmao" in discord it spits out this error:

Ignoring exception in on_message
Traceback (most recent call last):
  File "/opt/virtualenvs/python3/lib/python3.8/site->packages/discord/client.py", line 343, in _run_event
    await coro(*args, **kwargs)
  File "main.py", line 51, in on_message
    await message.channel.send('aantal keer lmao >gezegd:',aantlmao,'(sinds de laatste bot restart)')
TypeError: send() takes from 1 to 2 positional arguments but 4 were given
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Answer

It's happening because you passed 3 arguments (separated by commas) to send() in which you can pass only one. You should use string formatting to avoid this error:

await message.channel.send(f'aantal keer lmao gezegd: {aantlmao} (sinds de laatste bot restart)')

Edit:

Put your variable before your on_message event and add global before a variable to make it accessible in and outside your function:

aantlmao = 0

@client.event # you might be using @bot.event - it depends
async def on_message(message):
    global aantlmao

    if 'lmao' in message.content.lower():
        await message.channel.send(f'aantal keer lmao gezegd: {aantlmao} (sinds de laatste bot restart)')
        aantlmao += 1 # you can use the format you used before. This one is just a little bit better
        print('counted a LMAO')

Read this article about global, local, and nonlocal variables.

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source: stackoverflow.com
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