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Javascript Dealing With Unkown Number Of Function Arguments

- 1 answer

My function needs to accept any number of lists, then output their symmetric difference. sym([1, 2, 3], [5, 2, 1, 4]) should return [3, 5, 4] and sym([1, 2, 5], [2, 3, 5], [3, 4, 5]) should return [1, 4, 5]. How can I deal with the unknown number of arguments? I thought that I could use the single variable args to create a list of lists, but that isn't working.

function isin(num,arra)
{
  for (i=0; i<arra.length; i++)
  {
    if (num == arra[i]){return true;}
  }
  return false;
}

function sym(args) {
   var syms = [];
   console.log(args);
   for (i=0; i<args.length; i++)
   {
     var ins = false;
     for (j=0; j<args[i].length; j++)
     {
       for (k=i+1; k < args.length; k++)
       {
         if(isin(args[i][j], args[k]))
         {
           ins = true;
         }
       }
     }
     if (ins === false)
     {
       syms.push(args[i][j]);
     }
   }
  return syms;
}
sym([1, 2, 3], [5, 2, 1, 4]);
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Answer

use arguments, not args

and you dont need to have it in the function definition.

(note: Im assuming the rest of your code works once you actually get what youre expecting passed in)

so:

function sym() {
   var syms = [];
   console.log(arguments);
   for (i=0; i<argumentss.length; i++)
   {
     var ins = false;
     for (j=0; j<arguments[i].length; j++)
     {
       for (k=i+1; k < arguments.length; k++)
       {
         if(isin(arguments[i][j], arguments[k]))
         {
           ins = true;
         }
       }
     }
     if (ins === false)
     {
       syms.push(arguments[i][j]);
     }
   }
  return syms;
}
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source: stackoverflow.com
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