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How To Take Action Based On Detection Of Locked Or Off Screen In Flutter App
By using a flutter package from pub.dev named "torch_compat 1.0.2" for turning on/off flashlight in android app, how to turn off flashlight (trigger TorchCompat.turnOff()) when locked or off screen state detected.
Current code:
import 'package:flutter/material.dart';
import 'package:torch_compat/torch_compat.dart';
class FlashlightOnOffButton extends StatefulWidget {
@override
_FlashlightOnOffButtonState createState() => _FlashlightOnOffButtonState();
}
class _FlashlightOnOffButtonState extends State<FlashlightOnOffButton> {
bool isFlashlightOn = false;
@override
Widget build(BuildContext context) {
final data = MediaQuery.of(context);
var isPortrait = MediaQuery.of(context).orientation;
return Container(
child: FlatButton(
onPressed: () {
isFlashlightOn ? TorchCompat.turnOff() : TorchCompat.turnOn();
setState(() {
isFlashlightOn = !isFlashlightOn;
});
},
child: Icon(
Icons.lightbulb,
color: isFlashlightOn ? Colors.deepOrangeAccent : Colors.white10,
),
),
);
}
}
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Answer
Maybe your are looking for these packagepackage2
A more about flutter App Lifecycle may help you in achieving your desired results.
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source: stackoverflow.com
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