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How Can I Handle An Event To Open A Window In React Js?

- 1 answer

I want to open a window after clicking the fshare:

My render() return is like this

<Modal.Footer>
    <img src="/static/img/fshare.png" onClick={this.fbShare} />
    <Button onClick={this.hide}>Close</Button>
</Modal.Footer>

I am creating a function

fbShare: function(event) {

},

And I want to add the following code inside the function that basically opens a new window to share in Facebook:

window.open('https://www.facebook.com/dialog/feed?app_id=xxxxxxxxe='sharer', 'toolbar=0,status=0,width=548,height=325');" target="_parent" href="javascript: void(0)">

But I am confused with how to handle this event.

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Answer

You are on the right way!

Is it something you need? I prepared the example: click here

var Example = React.createClass({
    fbShare: function() {
        window.open('http://www.facebook.com/sharer.php?s=100&p[title]=Fb Share&p[summary]=Facebook share popup&p[url]=javascript:fbShare("http://jsfiddle.net/stichoza/EYxTJ/")&p[images][0]="http://goo.gl/dS52U"', 'sharer', 'toolbar=0,status=0,width=548,height=325');
    },

    render: function() {
        return (<div>
            <img src="http://pasadenainstitute.com/fb-shareTransp122x42.png" onClick={this.fbShare} />
        </div>);
    }
});

ReactDOM.render(
    <Example />,
    document.getElementById('container')
);
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source: stackoverflow.com
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